t^2-15t+100=0

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Solution for t^2-15t+100=0 equation: 



t^2-15t+100=0

a = 1; b = -15; c = +100;
Δ = b2-4ac
Δ = -152-4·1·100
Δ = -175
Delta is less than zero, so there is no solution for the equation

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